A C network is divided into four subnets, subnet 192.168.1.0
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Users questions: Problem: A C network is divided into four subnets, subnet 192.168.1.0 requirements: 1, write each subnet range. 2, write the number of hosts for each subnet. 3, write the steps in calculating (with the formula, then it also gave me bright, those on the power of 2.) I was like this: subnet 1:1 92.168.1.0 address range: 192.168.1.1 ~ 192.168.1.62 subnet 2:192.168.1.64 address range: 192.168.1.65 ~ 192.168.1.126 Subnet 3:192.168.1. 128 Address Range: 192.168.1.129 ~ 192.168.1.190 Subnet 4:192.168.1.192 address range: 19,
Experts answer: steps: 1. The words of the four subnets, each subnet as follows 192.168. 1.0 *** * 192. 168.1. 63192.168. 1.64 **- 192. 168.1. 127192.168. 1.128 ** 192. 168.1. 192192.168. 1.192 ** 192.168 . 1.255 each child Network IP address is 64, but is available in 62, one can not use one, the first is the network address, the tail is the host address. (So that the network will have eight addresses can not be used, the same token, the number of subnets by more then wasted the more IP addresses.) Calculation steps: What you want is four Subnet, it is the last one of (192.168.1.0, this refers to the 0 position) mask to cover the two, could have been 0,11000000 both a representative of the subnet number, 2 ^ 2 = 4 Well, then 0 for 6-bit hosts, 2 ^ 6 = 64, so that came out of a count
Experts answer: steps: 1. The words of the four subnets, each subnet as follows 192.168. 1.0 *** * 192. 168.1. 63192.168. 1.64 **- 192. 168.1. 127192.168. 1.128 ** 192. 168.1. 192192.168. 1.192 ** 192.168 . 1.255 each child Network IP address is 64, but is available in 62, one can not use one, the first is the network address, the tail is the host address. (So that the network will have eight addresses can not be used, the same token, the number of subnets by more then wasted the more IP addresses.) Calculation steps: What you want is four Subnet, it is the last one of (192.168.1.0, this refers to the 0 position) mask to cover the two, could have been 0,11000000 both a representative of the subnet number, 2 ^ 2 = 4 Well, then 0 for 6-bit hosts, 2 ^ 6 = 64, so that came out of a count
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