QQ upgrade problems, I now QQ upgrade, there's an active number of days calculated?
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Users questions:Requests the master to explain, if hanging a 24-hour day, and only an hour the same effect?
Experts answer: Hello! The user is currently level with the following conversion formula for calculating the number all day long "active days" of computing: the day (0:00-23:59) The use of QQ in 2 hours (and 2 hours or more)Accumulated an active day. Day (0:00-23:59) The use of QQ in 0.5 hours (includes 0.5 hours) to 2 hours, the cumulative activity of 0.5 days. Day (0:00-23:59) The use of QQ in the 0.5 hours the following, non-cumulative number of days assumed an active user's rating of N,Then the number of D for conversion all day: D = N * N +4 * N Example: Suppose there is a long-time user of their current level of 13, then converted into "active days" as: "active days" = 13 * 13 +4 * 13 = 221 days Note: If the user used today QQ3 hours, according to "active days" of theDefinition, we have their "active days of" cumulative 1 day, then the user's "activity days" for 222 days. If I were on-line 23:30, 1:30 off the assembly line, the server will be in a certain period of time a user of statistics when the long day online. 11:59 pm the previous section, counted into the total of the previous day's activity daysTime; 0:00, the count into the next day cumulative days of active time.
Experts answer: Hello! The user is currently level with the following conversion formula for calculating the number all day long "active days" of computing: the day (0:00-23:59) The use of QQ in 2 hours (and 2 hours or more)Accumulated an active day. Day (0:00-23:59) The use of QQ in 0.5 hours (includes 0.5 hours) to 2 hours, the cumulative activity of 0.5 days. Day (0:00-23:59) The use of QQ in the 0.5 hours the following, non-cumulative number of days assumed an active user's rating of N,Then the number of D for conversion all day: D = N * N +4 * N Example: Suppose there is a long-time user of their current level of 13, then converted into "active days" as: "active days" = 13 * 13 +4 * 13 = 221 days Note: If the user used today QQ3 hours, according to "active days" of theDefinition, we have their "active days of" cumulative 1 day, then the user's "activity days" for 222 days. If I were on-line 23:30, 1:30 off the assembly line, the server will be in a certain period of time a user of statistics when the long day online. 11:59 pm the previous section, counted into the total of the previous day's activity daysTime; 0:00, the count into the next day cumulative days of active time.
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